16x^2+88x=-40

Solution for 16x^2+88x=-40 equation:

16x^2+88x=-40

We move all terms to the left:

16x^2+88x-(-40)=0

We add all the numbers together, and all the variables

16x^2+88x+40=0

a = 16; b = 88; c = +40;
Δ = b2-4ac
Δ = 882-4·16·40
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-72}{2*16}=\frac{-160}{32}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+72}{2*16}=\frac{-16}{32}
=-1/2
$